Monday, May 30, 2016

Approximating ζ(s) between – 1 and – 2

We need to extend approximations for ζ(s), before suggesting a simple way of then achieving an approximation for any negative value.

Taking the central value – 1.5 (between – 1 and – 2),

ζ(– 1.5)  = – .025485...

This is well approximated by e – π(k) * 2k =  – .025408... (where k = 1.5)

I then attempted to obtain approximations based on this formula replacing the power (or exponent) with respect to both e and 2 with the corresponding value of k.

This works well down to k = 1.

However it is much more problematic in the other direction.

Here rather than changing k successively upwards from 1.6 to 2, it works better to decrease in again reaching k = 1 for s = – 2.

However even here the approximation proves very inaccurate as we approach s =  – 2, where ζ(– 2) = 0.

Once again I give a table showing values for s, ζ(s), approximation for ζ(s) and % relative accuracy.


              s
          ζ(s)
Approximation
% relative accuracy
         – 1.1
  – .067981
 – .067657
     99.5
         – 1.2
  – .054788
 – .052964
     96.7
         – 1.3
  – .043464
 – .041461
     95.4
         – 1.4
  – .033764
 – .032457
     96.1
         – 1.5
  – .025485
 – .025408
     99.7
         – 1.6
  – .018448
 – .017315
     93.9
         – 1.7
  – .012505
 – .011800
     94.3
         – 1.8
  – .007522
 – .008041
     93.5
         – 1.9
  – .003387
 – .005480
     61.8
         – 2.0
           0
 – .003734
        0

With the exception of the final two values, the approximations are quite accurate. It seems that the negative even values for s, where ζ(s) = 0, operate as attractors in their vicinity, upsetting previous trends.

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